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Hg(NO(3))(2) overset(Delta) to W + X + ...

`Hg(NO_(3))_(2) overset(Delta) to W + X + O_(2)`
`X + H_(2)O rarr HNO_(2) + HNO_(3)`
`W + HNO_(3) rarr Y + NO + H_(2)O`
`Y + Na_(2)S_(2)O_(3) ("excess") rarr Z + 2NaNO_(3)`

A

`{:("W"," X"," Y"," Z"),(Hg,NO,Hg(NO_(3))._(2),Na[Hg(S_(2)O_(3))_(2)]):}`

B

`{:("W"," X"," Y"," Z"),(Hg,NO_2,Hg(NO_(3))._(2),Na_2[Hg(S_(2)O_(3))_(2)]):}`

C

`{:("W"," X"," Y"," Z"),(Hg,N_(2)O,Hg(NO_(3))._(2),Na_(2)[Hg(S_(2)O_(3))_(2)]):}`

D

`{:("W"," X"," Y"," Z"),(Hg,N_(2)O_(3),Hg(NO_(3))._(2),Na_(3)[Hg(S_(2)O_(3))_(2)]):}`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given question step by step, we will analyze each reaction and identify the compounds W, X, Y, and Z. ### Step 1: Decomposition of Mercury(II) Nitrate The first reaction is: \[ \text{Hg(NO}_3\text{)}_2 \overset{\Delta}{\rightarrow} W + X + O_2 \] When mercury(II) nitrate is heated, it decomposes to form mercury (W), nitrogen dioxide (X), and oxygen gas. The balanced reaction is: \[ \text{Hg(NO}_3\text{)}_2 \rightarrow \text{Hg} + 2\text{NO}_2 + \text{O}_2 \] **Identifying W and X:** - W = Hg (Mercury) - X = NO₂ (Nitrogen Dioxide) ### Step 2: Reaction of Nitrogen Dioxide with Water The second reaction is: \[ X + H_2O \rightarrow HNO_2 + HNO_3 \] Here, nitrogen dioxide (X) reacts with water to form nitrous acid (HNO₂) and nitric acid (HNO₃). The balanced reaction is: \[ 2\text{NO}_2 + H_2O \rightarrow HNO_2 + HNO_3 \] ### Step 3: Reaction of Mercury with Nitric Acid The third reaction is: \[ W + HNO_3 \rightarrow Y + NO + H_2O \] Mercury (W) reacts with nitric acid to produce mercury(II) nitrate (Y), nitrogen monoxide (NO), and water. The balanced reaction is: \[ \text{Hg} + 4\text{HNO}_3 \rightarrow \text{Hg(NO}_3\text{)}_2 + 2\text{NO} + 2\text{H}_2O \] **Identifying Y:** - Y = Hg(NO₃)₂ (Mercury(II) Nitrate) ### Step 4: Reaction of Mercury(II) Nitrate with Sodium Thiosulfate The fourth reaction is: \[ Y + Na_2S_2O_3 \text{ (excess)} \rightarrow Z + 2NaNO_3 \] Mercury(II) nitrate (Y) reacts with excess sodium thiosulfate to form a complex and sodium nitrate. The balanced reaction is: \[ \text{Hg(NO}_3\text{)}_2 + 2\text{Na}_2\text{S}_2\text{O}_3 \rightarrow \text{Na}_2\text{HgS}_2\text{O}_3 + 2\text{NaNO}_3 \] **Identifying Z:** - Z = Na₂HgS₂O₃ (Sodium Thiosulfate Complex) ### Summary of Identifications - W = Hg (Mercury) - X = NO₂ (Nitrogen Dioxide) - Y = Hg(NO₃)₂ (Mercury(II) Nitrate) - Z = Na₂HgS₂O₃ (Sodium Thiosulfate Complex) ### Final Answer The correct option is **Option B**: - W = Hg - X = NO₂ - Y = Hg(NO₃)₂ - Z = Na₂HgS₂O₃ ---

To solve the given question step by step, we will analyze each reaction and identify the compounds W, X, Y, and Z. ### Step 1: Decomposition of Mercury(II) Nitrate The first reaction is: \[ \text{Hg(NO}_3\text{)}_2 \overset{\Delta}{\rightarrow} W + X + O_2 \] When mercury(II) nitrate is heated, it decomposes to form mercury (W), nitrogen dioxide (X), and oxygen gas. The balanced reaction is: \[ \text{Hg(NO}_3\text{)}_2 \rightarrow \text{Hg} + 2\text{NO}_2 + \text{O}_2 \] ...
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