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If orange turbidity appears on dilution...

If orange turbidity appears on dilution with `H_(2)O` of the solution in dil HCl , it is due to (a) ___and (b) _____ ion is assumed confirmed.

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To solve the question regarding the appearance of orange turbidity upon dilution with water of a solution in dilute HCl, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: The question states that orange turbidity appears when a solution in dilute HCl is diluted with water. We need to identify the ions responsible for this observation. 2. **Identifying Possible Compounds**: The orange turbidity is likely due to the formation of a specific compound. In qualitative inorganic analysis, one common compound that can cause orange turbidity is antimony sulfide (Sb₂S₃). 3. **Analyzing the Solubility**: Antimony sulfide is known to be soluble in concentrated hydrochloric acid (HCl) but becomes insoluble when the solution is diluted. This means that upon dilution with water, the antimony sulfide precipitates out of the solution, leading to the observed turbidity. 4. **Confirming the Ions**: The presence of orange turbidity indicates the presence of antimony ions (Sb³⁺) in the solution. When the solution is diluted, the antimony ions react to form antimony oxychloride (SbOCl), which is also a possible contributor to the orange color. 5. **Final Conclusion**: Based on the above analysis, we can conclude that: - (a) The first ion responsible for the orange turbidity is **SbOCl** (antimony oxychloride). - (b) The second ion confirmed is **Sb³⁺** (antimony ion). ### Final Answer: (a) SbOCl (b) Sb³⁺ ion is assumed confirmed. ---
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CENGAGE CHEMISTRY ENGLISH-QUALITATIVE INORGANIC SALT ANALYSIS-Exercises (Fill In The Blanks)
  1. Cr(OH)(3) is made soluble in NaOH in presence of (a) when (b) of(c ) ...

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  2. Fe(OH)(3) and Al(OH)(3) ppt. can be separated by (a) when (b) becomes ...

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  3. If orange turbidity appears on dilution with H(2)O of the solution ...

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  4. Copper sub-group ppt. and arsenic salt -group ppt. are sepeated using ...

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  5. PbCl(2) is soluble in (a) . AgCl is soluble in (b) white Hg(2)Cl(2) i...

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  6. Cd^(2+) and Cu^(2+) are seprated by (a) formation using (b) in which ...

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  7. Precipitation of Cd^(2+) and Cu^(2+) takes place in presence of (a)by ...

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  8. NH(4)Cl is added along with NH(4)OH in group (a)to (b) concentration o...

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  9. Separation of basic radicals is based on (a) and (b) .

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  10. Gas that turns lime water milky and aciddied K(2)Cr(2)O(7) green is...

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  11. NH(4)SCN gives red colour with (s) due to the formation of (b) .

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  12. HgCl(2) gives orange ppt , with (a) , which dissolves in excess of i...

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  13. Al(OH)(3) is precipitate if its produces (a)is (b) that K(sp)

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  14. PbSO(4) is soluble in (a) due to formation of (b) .

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  15. A reagent that can detect any of Cu^(2+),Fe^(3+),Zn^(2+) and Cd^(2+) i...

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  16. Fe^(2+) gives blue coloue, called(a) with (b)white Fe^(2+) gives blue ...

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  17. Ferric alum is the indicator in the titration of Ag^(o+) with SCN^(Θ)...

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  18. FeC(2)O(4) can decolorise acidified KMnO(4) due to the oxidation of (...

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  19. Acidified KMnO(4) can be decolourised by (a).

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  20. Iron (II)sulphide gives foul smell of (a).

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