`Al(OH)_(3)` is precipitate if its produces (a)____is (b) ____ that `K_(sp)`

Answer

To solve the question regarding the precipitation of aluminum hydroxide, \( Al(OH)_3 \), we will follow these steps:

### Step-by-Step Solution:

1. **Identify the ions produced during precipitation:**
- When aluminum hydroxide, \( Al(OH)_3 \), precipitates, it dissociates into its constituent ions. The ions produced are:
- \( Al^{3+} \) (aluminum ion)
- \( OH^{-} \) (hydroxide ion)
- Therefore, the answer for part (a) is:
- **(a)** \( Al^{3+} \) and \( 3OH^{-} \)

2. **Determine the solubility product constant (\( K_{sp} \)):**
- The solubility product constant \( K_{sp} \) for aluminum hydroxide can be expressed based on the dissociation:
\[ K_{sp} = [Al^{3+}][OH^{-}]^3 \]
- For precipitation to occur, the ionic product must exceed the \( K_{sp} \) value. Thus, the condition for precipitation is that the product of the concentrations of the ions must be greater than \( K_{sp} \).
- Therefore, the answer for part (b) is:
- **(b)** Greater than \( K_{sp} \)

### Final Answers:
- (a) \( Al^{3+} \) and \( 3OH^{-} \)
- (b) Greater than \( K_{sp} \)