When `SO_(2)` is passed into suspention of `CaSO_(3)` in water (a) _____ is formed.

Answer

To solve the question, we need to understand the reaction that occurs when sulfur dioxide (SO₂) is passed into a suspension of calcium sulfide (CaSO₃) in water. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Reactants
- The reactants in this scenario are sulfur dioxide (SO₂) and calcium sulfide (CaSO₃) suspended in water.

### Step 2: Understand the Reaction
- When sulfur dioxide is introduced to calcium sulfide in water, a chemical reaction takes place. Initially, calcium sulfide (CaSO₃) is a solid that can react with sulfur dioxide.

### Step 3: Formation of Calcium Sulfite
- The first product formed when SO₂ is passed into the suspension is calcium sulfite (CaSO₃). This compound is typically a white precipitate.

### Step 4: Excess SO₂ and Formation of Calcium Bisulfite
- If an excess of sulfur dioxide is added to the suspension, the calcium sulfite can further react with the additional SO₂. This results in the formation of calcium bisulfite (Ca(HSO₃)₂), which is a soluble compound in water.

### Step 5: Conclusion
- Therefore, when sulfur dioxide is passed into a suspension of calcium sulfide in water, the final soluble product formed is calcium bisulfite (Ca(HSO₃)₂).

### Final Answer
When SO₂ is passed into a suspension of CaSO₃ in water, **calcium bisulfite (Ca(HSO₃)₂)** is formed.

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