`BaBr_(2)` in aq solution give yellow ppt ,with (a)____ as well as with (b)___.

Answer

To solve the question regarding the yellow precipitate formed when barium bromide (BaBr₂) is mixed with certain reagents, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction of BaBr₂ with Potassium Chromate (K₂CrO₄)**:
- When barium bromide (BaBr₂) reacts with potassium chromate (K₂CrO₄), a double displacement reaction occurs.
- The products of this reaction are barium chromate (BaCrO₄), which is a yellow precipitate, and potassium bromide (KBr).
- The balanced chemical equation for this reaction is:
\[ BaBr_2 (aq) + K_2CrO_4 (aq) \rightarrow BaCrO_4 (s) + 2 KBr (aq) \]

2. **Identify the Reaction of BaBr₂ with Silver Nitrate (AgNO₃)**:
- Next, when barium bromide (BaBr₂) is mixed with silver nitrate (AgNO₃), another double displacement reaction occurs.
- The products formed are silver bromide (AgBr), which is a light yellow precipitate, and barium nitrate (Ba(NO₃)₂).
- The balanced chemical equation for this reaction is:
\[ BaBr_2 (aq) + 2 AgNO_3 (aq) \rightarrow 2 AgBr (s) + Ba(NO_3)_2 (aq) \]

3. **Conclusion**:
- Therefore, barium bromide (BaBr₂) in aqueous solution gives a yellow precipitate with:
(a) Potassium chromate (K₂CrO₄)
(b) Silver nitrate (AgNO₃)

### Final Answer:
Barium bromide in aqueous solution gives yellow precipitate with (a) K₂CrO₄ as well as with (b) AgNO₃.

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