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The pair of compounds which cannot exist...

The pair of compounds which cannot exist together in aqueous solution is ,
(I)`NaH_(2)PO_(4) and NaHCO_(3)` (II)`Na_(2)CO_(3) and NaHCO_(3)` (III)`NaOH and NaH_(2)PO_(4)` (IV)`NaHCO_(3) and NaOH`

A

`NaHCO_(3) and NaOH`

B

`Na_(2)CO_(3) and NaHCO_(3)`

C

`Na_(2)CO_(3) and NaOH`

D

`NaHCO_(3)` and `NaCI`

Text Solution

Verified by Experts

The correct Answer is:
a

`NaHCO_(3)` and `NaOH`cannot coexist in solution because `NaHCO_(3)` is an acid sqalt it reacts with the base `NaOH` as follows
`NaHCO_(3) + NaOH rarr Na_(2)CO_(3) +H_(2)O`
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The pair of compounds which cannot exist together in aqueous solution is: (I) NaH_(2)PO_(4) and NaHCO_(3)" "(II) Na_(2)CO_(3) and NaHCO_(3) (III) NaOH and NaH_(2)PO_(2)" "(IV) NaHCO_(3) and NaOH

The pairs of compounds which cannot exist together in aquous solution are: (I) NaH_(2)PO_(4) and Na_(2)HCO_(3) (II) Na_(2)CO_(3) and NaOH (III) NaOH and NaH_(2)PO_(4) (IV) NaHCO_(3) and NaOH

NaHCO_(3) and NaOH cannot exist together in solution. Why ?

P_(4)+NaOH to PH_(3) uarr+NaH_(2)PO_(2)

P_(4)+NaOH to PH_(3) uarr+NaH_(2)PO_(2)

During the titration of a mixture of Na_(2)CO_(3) and NaHCO_(3) against HCl :

Which one is the formula of baking soda? Na_(2)CO_(3) NaOH KHCO_(3) NaHCO_(3)

Give the n factors for the following changes - (i) Na_(2) CO_(3) rarr NaHCO_(3) (ii) Al_(2) (SO_(4))_(3) rarr Al(OH)_(3) (ii) Na_(2) S_(2) O_(3) rarr S_(4) O_(6)^(-2)

Percentage loss in mass, when NaHCO_(3)(s) is heated in open vessel 2NaHCO_(3)(s)rarrNa_(2)CO_(3)(s)+CO_(2)(g)+H_(2)O(g)

The chemical name of NaH_(2)PO_(4) is -

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