During the quation analysis of a mixture containing `Cu^(2+) and Zn^(2+) ions H_(2)S` gas is passed therough an acidified solution containing these ions in order to test `Cu^(2+)` alone explane

Explanation

To explain the qualitative analysis of a mixture containing \( \text{Cu}^{2+} \) and \( \text{Zn}^{2+} \) ions when \( \text{H}_2\text{S} \) gas is passed through an acidified solution, we can follow these steps:

### Step 1: Preparation of the Solution
- Begin by preparing an acidified solution of the mixture containing \( \text{Cu}^{2+} \) and \( \text{Zn}^{2+} \) ions. This is typically done by adding hydrochloric acid (HCl) to the solution.

### Step 2: Reaction with HCl
- When \( \text{HCl} \) is added to the solution, it dissociates into \( \text{H}^+ \) ions and \( \text{Cl}^- \) ions. The \( \text{Cu}^{2+} \) ions react with the chloride ions to form copper(II) chloride:
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