A white substance A reacts with dilute `H_(2)SO_(4)` is produce a colourless B and acidified `K_(2)Cr_(2)O_(7)` solution produces a green solution and a slighly coloured precipitate D .The substance B to burns in air to produce a gas E which reacts with B ito yied D and a colouless liquid .Anhyhdrous copper sulphate is turned blue on addition of this colourless liquid addition od aqueous `NH_(3) or NaOH` to C produce first a precipitate which dissolve in the excess of the respective reagent to produce a clear solution in each case identify A,B,C, and E. Write the equation of the reaction involved.

Explanation

To solve the problem step by step, we will identify the compounds A, B, C, D, and E based on the reactions described in the question.

### Step 1: Identify Substance A
The question states that a white substance A reacts with dilute `H2SO4` to produce a colorless gas B. Given that the gas is colorless and the reaction involves a white substance, we can assume that A is a sulfide, specifically **zinc sulfide (ZnS)**. When ZnS reacts with dilute sulfuric acid, it produces **hydrogen sulfide (H2S)**, which is the colorless gas B.

**Reaction:**
\[ \text{ZnS} + \text{H}_2\text{SO}_4 \rightarrow \text{ZnSO}_4 + \text{H}_2\text{S} \]

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