For testing `SO_(4)^(2-)` with `BaCl_(2)` solution why should sodium carbonate not be acidified with too much of conc. HCl.

Explanation

To answer the question of why sodium carbonate should not be acidified with too much concentrated HCl when testing for sulfate ions with barium chloride, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Reaction**: When sodium carbonate (Na2CO3) is acidified with concentrated hydrochloric acid (HCl), it produces carbon dioxide (CO2), water (H2O), and sodium chloride (NaCl). The reaction can be represented as:
\[ Na_2CO_3 + 2HCl \rightarrow 2NaCl + H_2O + CO_2 \uparrow \]
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