Give the decreasing order of the stabilities of the following free radicals :
(a) `Ph dot C H Ph`
(b) `Ph dot CHCH=CH_2`
( c) `Me dot CHMe`
(d) `Ph dot CHMe`
( e) `MeCH=CHCH_2 dot CH_2`
(f) `Et- dot C- Me_2`.

Explanation

To determine the decreasing order of stability of the given free radicals, we will analyze each radical based on two main factors: resonance stabilization and the inductive effect (plus I effect). Let's evaluate each radical step by step.

### Step 1: Analyze each free radical

1. **(a) `Ph dot C H Ph`**:
- This radical has two phenyl (Ph) groups attached to the carbon with the unpaired electron. The resonance from both phenyl groups stabilizes the radical significantly.
- **Stability**: Very high due to double resonance.

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