Give the equation of methanolysis of `[Me_3CSMe_(2)]^(oplus) Br^(Ө)`.

Explanation

To solve the question regarding the methanolysis of the compound \([Me_3CSMe_2]^+ Br^-\), we can break down the process step by step.

### Step 1: Identify the Structure
The compound \([Me_3CSMe_2]^+ Br^-\) consists of a tert-butyl group \((Me_3C)\) attached to a sulfur atom that is further attached to two methyl groups \((SMe_2)\). The bromide ion \((Br^-)\) is the counterion associated with the positively charged species.

### Step 2: Understand the Reaction
In a methanolysis reaction, methanol \((CH_3OH)\) acts as a nucleophile. The positively charged carbon atom (from the tert-butyl group) will attract the nucleophile, leading to the substitution of the leaving group (in this case, the bromide ion).

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