Neutralisation of `0.3504 gm` of acid `(A)` requires `27.24 ml` of `0.15 M NaOH`, and the `Mw` is found from the mass spectral data to be `172.1 gm mol^-1`.
(a) Calculate the `N.R` of `(A)`.
(b) How many ionisable `H` atom are there in `(A)` ?

Explanation

To solve the problem step by step, we will break it down into two parts as per the question.

### Part (a): Calculate the Normality (N.R) of Acid (A)

1. **Calculate the moles of NaOH used in the neutralization:**
\[ \text{Moles of NaOH} = \text{Molarity} \times \text{Volume (in L)} \]
...