Which carboxylic acid `(B) (N.E = 52 gm eq^-1)` loses `CO_2` when heated to give an acid `( C) N.E = 60 gm eq^(-1)` ?

Explanation

To solve the problem, we need to identify the carboxylic acid (B) that has a neutralization equivalent (N.E) of 52 g/eq and loses CO₂ upon heating to yield another acid (C) with a neutralization equivalent of 60 g/eq.

### Step-by-Step Solution:

1. **Understanding Neutralization Equivalent**:
The neutralization equivalent (N.E) of a carboxylic acid is defined as the molecular weight of the acid divided by the number of acidic protons (H⁺) it can donate. For monocarboxylic acids, the N.E is equal to the molecular weight.

2. **Identifying Acid C**:
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