An organic diabasic acid `(A)` gave the following on analysis :
`C = 57.8 %, H = 3.6 %`. Its silver salt contained `56.8 % Ag`. On heating `(A)` gives a product `(B)` which on heating with `NH_3`gives `( C) (C_8 H_5 O_2 N)`. Compound `( C)` forms potassium salt with alc. `KOH` and is converted into o-aminobenzoic acid with `NaClO`. Assign structures to `(A), (B),` and `( C)`.

Explanation

To solve the problem step by step, we will analyze the information provided and deduce the structures of compounds A, B, and C.

### Step 1: Determine the molecular formula of compound A
Given the percentage composition of compound A:
- Carbon (C) = 57.8%
- Hydrogen (H) = 3.6%

Assuming we have 100 g of compound A:
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