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underset((A))(PhCOOH) overset((i) N2 H,H...

`underset((A))(PhCOOH) overset((i) N_2 H,H^(oplus)) underset((ii) Delta)rarr (B) overset(H_2 O // overset(Ө)OH)rarr (C)`
Which of the following statement is /are correct about the reaction ?

A

The compounds `(B)` and `( C)`, respectively, are `Ph-N=C=O` and `PhNH_2`.

B

The compounds `(B)` and `( C)`, respectively, are `Ph overset(oplus) N -= overset (Ө) C` and `PhNHMe`.

C

The reaction is known as Curtius rearrangement reaction.

D

The reaction is known as Schmidt rearrangement reaction.

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The correct Answer is:
To analyze the reaction provided in the question, we will break it down step by step, focusing on the transformation of benzoic acid (PhCOOH) through the specified reactions. ### Step 1: Identify the Reactants The starting compound is benzoic acid (PhCOOH). ### Step 2: First Reaction with N2H4 in Acidic Medium In the first step, benzoic acid reacts with hydrazine (N2H4) in an acidic medium (H⁺). This reaction typically leads to the formation of a hydrazone derivative. The hydroxyl group (OH) from the carboxylic acid and a hydrogen (H) from hydrazine combine to form water (H2O), resulting in the formation of a new compound. **Formation of Compound B:** - The reaction can be summarized as: \[ \text{PhCOOH} + \text{N}_2\text{H}_4 \xrightarrow{H^+} \text{Compound B} \] ### Step 3: Heating the Product Next, the product (Compound B) is heated. During this step, a rearrangement occurs where nitrogen leaves the structure, potentially leading to the formation of an intermediate compound. ### Step 4: Rearrangement Reaction The rearrangement that occurs is known as the Claisen-Bischoff rearrangement. In this reaction, the phenyl group (Ph) attacks the nitrogen, leading to the formation of a new compound. **Formation of Compound C:** - The reaction can be summarized as: \[ \text{Compound B} \xrightarrow{\Delta} \text{Compound C} \] ### Step 5: Reaction with Water in Basic Medium Finally, Compound C is treated with water in a basic medium (OH⁻). This leads to the hydrolysis of the compound, resulting in the formation of aniline (PhNH2) and the release of carbon dioxide (CO2). ### Conclusion The final products of the reaction sequence are: - Compound B: An intermediate formed after the first reaction. - Compound C: Aniline (PhNH2). ### Summary of Statements 1. **Statement A**: Correct, as it describes the formation of Compound B and C accurately. 2. **Statement B**: Incorrect, as it mentions wrong products. ### Final Answer The correct answer will be the statements that accurately describe the reaction and products formed. ---

To analyze the reaction provided in the question, we will break it down step by step, focusing on the transformation of benzoic acid (PhCOOH) through the specified reactions. ### Step 1: Identify the Reactants The starting compound is benzoic acid (PhCOOH). ### Step 2: First Reaction with N2H4 in Acidic Medium In the first step, benzoic acid reacts with hydrazine (N2H4) in an acidic medium (H⁺). This reaction typically leads to the formation of a hydrazone derivative. The hydroxyl group (OH) from the carboxylic acid and a hydrogen (H) from hydrazine combine to form water (H2O), resulting in the formation of a new compound. ...
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