`Identity`(X):`CHCl_(3)overset(SbF_(3))underset(HF)rarrCHF_(2)Cloverset(1070K)rarr(X)+2HCl`

Options

A. `F_(2)C=CF_(2)`
B. `CIFC=CFCl`
C. `F_(2)C=CFCl`
D. `F_(2)C=CCl_(2)`

Answer

To identify the compound X in the given reaction, we can follow these steps:

### Step 1: Understand the Reaction
The reaction starts with chloroform (CHCl₃) reacting with antimony trifluoride (SbF₃) and hydrofluoric acid (HF). This is a substitution reaction where chlorine atoms in chloroform are replaced by fluorine atoms.

### Step 2: Identify the Product from the First Reaction
When chloroform (CHCl₃) reacts with SbF₃ and HF, two chlorine atoms are replaced by fluorine atoms. The product formed is difluorochloroethane, which is CHF₂Cl.

### Step 3: Analyze the Second Reaction
The next step involves heating CHF₂Cl at 1070 K. This heating causes the elimination of HCl. Since we have two moles of CHF₂Cl, we can visualize the reaction as follows:
- Two CHF₂Cl molecules will lose HCl, resulting in the formation of a double bond between the two carbon atoms.

### Step 4: Determine the Structure of X
After the elimination of HCl, the resulting compound will have the structure of CF₂=CF₂. This compound is known as tetrafluoroethylene.

### Step 5: Conclusion
Therefore, the compound X is identified as tetrafluoroethylene (CF₂=CF₂).

### Final Answer
The compound X is tetrafluoroethylene (CF₂=CF₂).

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