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IfN(1),N(2),N(3),……are the number of mol...

If`N_(1),N_(2),N_(3),……`are the number of molcules with molecular masses `M_(1),M_(2),(M_(3),…`respectively ,then mass average molar mass is expressed as:

A

`(N_(1)M_(1)^(2),N_(2)M_(2)^(2),+……)/((N_(1)M_(1),N_(2)M_(2),+……))=(SigmaNiMi^(2))/(SigmaNiMi)`

B

`(N_(1)M_(1),N_(2)M_(2),+……)/((N_(1),N_(2),+……))=(SigmaNiMi)/(SigmaNi)`

C

`(SigmaMi^(2))/(SigmaNi)`

D

`(SigmaNiMi)/(SigmaMi)`

Text Solution

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The correct Answer is:
To find the mass average molar mass given the number of molecules and their respective molecular masses, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Variables**: - Let \( N_1, N_2, N_3, \ldots \) be the number of molecules. - Let \( M_1, M_2, M_3, \ldots \) be the respective molecular masses of these molecules. 2. **Identify the Formula for Mass Average Molar Mass**: - The mass average molar mass (also known as weight average molecular mass) is calculated using the formula: \[ \bar{M}_w = \frac{\sum (N_i \cdot M_i^2)}{\sum (N_i \cdot M_i)} \] where \( \bar{M}_w \) is the mass average molar mass, \( N_i \) is the number of molecules, and \( M_i \) is the molecular mass of each type of molecule. 3. **Calculate the Numerator**: - The numerator is the sum of the products of the number of molecules and the square of their respective molecular masses: \[ \text{Numerator} = N_1 \cdot M_1^2 + N_2 \cdot M_2^2 + N_3 \cdot M_3^2 + \ldots \] 4. **Calculate the Denominator**: - The denominator is the sum of the products of the number of molecules and their respective molecular masses: \[ \text{Denominator} = N_1 \cdot M_1 + N_2 \cdot M_2 + N_3 \cdot M_3 + \ldots \] 5. **Combine the Results**: - Finally, substitute the results from the numerator and denominator into the formula to get the mass average molar mass: \[ \bar{M}_w = \frac{N_1 \cdot M_1^2 + N_2 \cdot M_2^2 + N_3 \cdot M_3^2 + \ldots}{N_1 \cdot M_1 + N_2 \cdot M_2 + N_3 \cdot M_3 + \ldots} \] ### Final Answer: The mass average molar mass is expressed as: \[ \bar{M}_w = \frac{\sum (N_i \cdot M_i^2)}{\sum (N_i \cdot M_i)} \]
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