The structures to two compound `(I)` and `(II)` are given below.
Which statement is correct ?
`F_(2)C=C=CF_(2)(I)` and `F_(2)C=C=C=CF_(2)(II)`

Options

A. Reductive ozonolysis of both gave the same product.
B. Reductive ozonolysis of both gave different products.
C. Reductive and oxidative ozonolysis of both gave different products.
D. Reductive and oxidative ozonolysis of `(I)` gave the same product
but of `(II)` gave different products.

Explanation

To determine which statement is correct regarding the compounds \( F_2C=C=CF_2 \) (I) and \( F_2C=C=C=CF_2 \) (II), we will analyze the structures and the results of reductive ozonolysis for both compounds.

### Step 1: Identify the Structures
1. **Compound I**: \( F_2C=C=CF_2 \)
- This compound has a double bond between the two carbon atoms with fluorine substituents.

2. **Compound II**: \( F_2C=C=C=CF_2 \)
- This compound has a conjugated system with two double bonds, meaning it has a more complex structure.

**Hint**: Draw the structures of both compounds to visualize the differences in bonding and substituents.

### Step 2: Understand Reductive Ozonolysis
Reductive ozonolysis involves the reaction of alkenes with ozone (O₃) followed by a reducing agent (like zinc in acetic acid). This process cleaves the double bonds and forms carbonyl compounds.

**Hint**: Recall that ozonolysis breaks double bonds and can lead to the formation of aldehydes, ketones, or carboxylic acids depending on the structure of the alkene.

### Step 3: Predict the Products
1. **For Compound I**:
- The ozonolysis will cleave the double bond between the two carbon atoms.
- This will yield two molecules of difluoroacetaldehyde (\( F_2C=O \)) and carbon dioxide (CO₂) as a byproduct.

2. **For Compound II**:
- The ozonolysis will cleave both double bonds.
- This will yield two molecules of difluoroacetaldehyde (\( F_2C=O \)) and two molecules of carbon dioxide (CO₂) as byproducts.

**Hint**: Write down the expected products for each compound after ozonolysis to compare them.

### Step 4: Compare the Products
- From the ozonolysis of both compounds, we find that:
- **Compound I** produces: \( 2 \, F_2C=O + CO_2 \)
- **Compound II** produces: \( 2 \, F_2C=O + 2CO_2 \)

**Hint**: Focus on the number of carbon dioxide molecules produced as a key difference in the products.

### Step 5: Conclusion
Both compounds yield the same type of carbonyl product (difluoroacetaldehyde), but the number of carbon dioxide molecules produced is different. Therefore, the correct statement regarding these compounds is that the reductive ozonolysis of both compounds gives the same product but with a different number of moles of carbon dioxide.

**Final Answer**: The reductive ozonolysis of both compounds yields the same product, but Compound II produces one additional mole of carbon dioxide compared to Compound I.