(A) `A(C_(7)H_(14)) overset(O_(3)//Red)(rarr)B(C_(3)H_(6)O)+C`
(B) Gives positive Tollens test but negative iodform test.
(C ) Give negative Tollens test but positive iodoform test.
The compound (C ) is:

Options

A. a.
B. b.
C. c.
D. d.Both `(a)` and `(c )`

Answer

To solve the problem step by step, let's analyze the information provided and derive the required compound (C).

### Step 1: Identify the structure of compound A
- Given that compound A has the formula \(C_7H_{14}\), it is likely an alkene. The simplest structure for an alkene with this formula is heptene.

### Step 2: Understand the ozonolysis reaction
- Ozonolysis of alkenes typically results in the formation of carbonyl compounds (aldehydes and/or ketones). When heptene undergoes ozonolysis, it will break down into two products.

### Step 3: Identify the products B and C
- The products of ozonolysis will be:
- **B**: An aldehyde (which gives a positive Tollens test and a negative iodoform test).
- **C**: A ketone (which gives a negative Tollens test and a positive iodoform test).

### Step 4: Analyze the tests
- **Tollens test**: Positive for aldehydes and negative for ketones.
- **Iodoform test**: Positive for methyl ketones (ketones with the structure \(RCOCH_3\)) and negative for aldehydes.

### Step 5: Determine the structure of compound B
- Since B gives a positive Tollens test and a negative iodoform test, it must be an aldehyde. The likely candidate from the ozonolysis of heptene is propanal (\(CH_3CH_2CHO\)).

### Step 6: Determine the structure of compound C
- Since C gives a negative Tollens test and a positive iodoform test, it must be a ketone. The likely candidate from the ozonolysis of heptene is butanone (\(CH_3COCH_2CH_3\)).

### Conclusion
- Therefore, the compound C is butanone.

### Final Answer
The compound C is **butanone**.

---