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(A) A(C(7)H(14)) overset(O(3)//Red)(rarr...

(A) `A(C_(7)H_(14)) overset(O_(3)//Red)(rarr)B(C_(3)H_(6)O)+C`
(B) Gives positive Tollens test but negative iodform test.
(C ) Give negative Tollens test but positive iodoform test.
The compound (B) can be converted to (C ) by using the reagents:

A

a.i. `EtMgBr//H_(3)O^(o+)`, ii. `Acidic KMnO_(4)`

B

b.i. `MeMgBr//H_(3)O^(o+)`, ii. `Acidic KMnO_(4)`

C

c.i. `EtMgBr//H_(3)O^(o+)`, ii. `Aqueous KMnO_(4)`

D

d.i. `MeMgBr//H_(3)O^(o+)`, ii. `Aqueous KMnO_(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question step by step, we will analyze the information provided and identify the compounds involved in the reactions. ### Step 1: Identify Compound A - Given that compound A has the formula \( C_7H_{14} \), it is an alkene. The structure of heptene (the alkene with 7 carbon atoms) can be represented as: \[ \text{Heptene: } CH_3-CH_2-CH_2-CH_2-CH=CH-CH_3 \] ### Step 2: Ozonolysis of Compound A - When heptene undergoes ozonolysis (reaction with ozone), it will break down into two products: an aldehyde (compound B) and a ketone (compound C). - The ozonolysis of heptene will yield: \[ \text{Aldehyde (B): } CH_3CH_2CHO \quad (\text{propanal}) \] \[ \text{Ketone (C): } CH_3COCH_2CH_3 \quad (\text{butanone}) \] ### Step 3: Analyze the Tests for Compounds B and C - **Compound B (propanal)** gives a positive Tollens test (indicating the presence of an aldehyde) and a negative iodoform test (since propanal does not have a methyl ketone structure). - **Compound C (butanone)** gives a negative Tollens test (as it is a ketone) but a positive iodoform test (since butanone has a methyl group adjacent to the carbonyl). ### Step 4: Converting Compound B to Compound C - To convert compound B (propanal) to compound C (butanone), we can use the following reagents: 1. **Methyl magnesium bromide (Grignard reagent)**: This will react with propanal to form 2-butanol. 2. **Acidic KMnO4**: This will oxidize 2-butanol to butanone. ### Step 5: Write the Reactions 1. **Formation of 2-butanol from propanal**: \[ CH_3CH_2CHO + CH_3MgBr \xrightarrow{H_3O^+} CH_3CH(OH)CH_2CH_3 \quad (\text{2-butanol}) \] 2. **Oxidation of 2-butanol to butanone**: \[ CH_3CH(OH)CH_2CH_3 \xrightarrow{KMnO_4} CH_3COCH_2CH_3 \quad (\text{butanone}) \] ### Final Answer - The reagents needed to convert compound B to compound C are: - **Methyl magnesium bromide (Grignard reagent) followed by acidic KMnO4**.

To solve the question step by step, we will analyze the information provided and identify the compounds involved in the reactions. ### Step 1: Identify Compound A - Given that compound A has the formula \( C_7H_{14} \), it is an alkene. The structure of heptene (the alkene with 7 carbon atoms) can be represented as: \[ \text{Heptene: } CH_3-CH_2-CH_2-CH_2-CH=CH-CH_3 \] ...
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