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Statement 1: Acryaldehyde (CH(2)=CH-CHO)...

Statement 1: Acryaldehyde `(CH_(2)=CH-CHO)` is oxidised to acrylic acid
`(CH_(2)==CH-COOH)` by Benedict's solution.
Statement 2: Benedict's solution is ammoniacal `CuSO_(4)` solution containing sodium potassium tartarate.

A

a.Statement 1 and Statement 2 are true and Statement 2 is the correct explanation of Statement 1.

B

b.Statement 1 and Statement 2 are true and Statement 2 is not the correct explanation of Statement 1.

C

c.Statement 1 is true and statement 2 is false.

D

d.Statement 1 is false and statement 2 is false

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both statements provided regarding the oxidation of acrylaldehyde and the composition of Benedict's solution. ### Step-by-Step Solution: 1. **Understanding Statement 1:** - The first statement claims that acrylaldehyde (CH₂=CH-CHO) is oxidized to acrylic acid (CH₂=CH-COOH) by Benedict's solution. - **Oxidation Process:** In this reaction, the aldehyde group (CHO) in acrylaldehyde is oxidized to a carboxylic acid group (COOH) in acrylic acid. - **Benedict's Solution Function:** Benedict's solution is known to oxidize aldehydes to carboxylic acids. It contains cupric ions (Cu²⁺) that can be reduced to cuprous ions (Cu⁺) while oxidizing the aldehyde. - **Conclusion for Statement 1:** This statement is **true** because acrylaldehyde can indeed be oxidized to acrylic acid using Benedict's solution. 2. **Understanding Statement 2:** - The second statement describes Benedict's solution as an ammoniacal CuSO₄ solution containing sodium potassium tartrate. - **Composition of Benedict's Solution:** While it does contain copper sulfate and is ammoniacal, the key component that complexes with Cu²⁺ ions is actually sodium citrate, not sodium potassium tartrate. - **Conclusion for Statement 2:** This statement is **false** because the correct complexing agent in Benedict's solution is sodium citrate, not sodium potassium tartrate. 3. **Final Conclusion:** - Since Statement 1 is true and Statement 2 is false, the correct answer to the question is that only Statement 1 is correct. ### Answer: - **Correct Option:** Statement 1 is true, Statement 2 is false.

To solve the question, we need to analyze both statements provided regarding the oxidation of acrylaldehyde and the composition of Benedict's solution. ### Step-by-Step Solution: 1. **Understanding Statement 1:** - The first statement claims that acrylaldehyde (CH₂=CH-CHO) is oxidized to acrylic acid (CH₂=CH-COOH) by Benedict's solution. - **Oxidation Process:** In this reaction, the aldehyde group (CHO) in acrylaldehyde is oxidized to a carboxylic acid group (COOH) in acrylic acid. - **Benedict's Solution Function:** Benedict's solution is known to oxidize aldehydes to carboxylic acids. It contains cupric ions (Cu²⁺) that can be reduced to cuprous ions (Cu⁺) while oxidizing the aldehyde. ...
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