An aromatic hydrocarbobn `(A)` containing `C = 91.3%` and `H = 8.7%` on treatment with chlorine gave there isomeric monochloro compound `(X),(Y)` and `(Z)`, each having `28%` chlorine . On oxidation with `KMnO_(4)` all the three gave monobasic acids. The acid form `(X)` on distillation with soda line gave benzene while those form `(Y)` and `(Z)` gave monochlorobenzene. What formula would you assign to the various compounds?

Explanation

To solve the problem, we will follow these steps systematically:

### Step 1: Determine the empirical formula of compound (A)
Given the percentage composition of compound (A):
- Carbon (C) = 91.3%
- Hydrogen (H) = 8.7%

To find the empirical formula, we convert the percentages to grams (assuming 100 g total):
...