On nuclear chlorination, `C_(8), H_(10) (A)` gives a product `(B)` which may be oxidised to `C_(8) H_(5)O_(4)Cl(C). (A)` may alos be chlorinated to give `C_(8) H_(8) Cl_(2)(D), C_(8) H_(6)Cl_(4)(E)`, and `C_(8) H_(4) Cl_(6)(F). (D), (E)` and `(F)` on hydrolysis give halogen-free compounds `(G), (H)`, and `(I)`, respectively. With `CrCO_(2)Cl_(2), (A)` gives `C_(8) H_(6)O_(4)` which is identiacla with `(I)` . Identify wtih `(I)`. Identify the varioius compounds `(A)` to `(J)`.

Explanation

To solve the problem step by step, we will identify the compounds A to J based on the information provided in the question and the video transcript.

### Step 1: Identify Compound A
The question states that compound A has the formula C₈H₁₀. A common compound with this formula is p-xylene, which has two methyl groups attached to a benzene ring.

**Compound A: p-xylene (C₆H₄(CH₃)₂)**

### Step 2: Chlorination of Compound A to form Compound B
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