When boromobenze is monochlorinated. Two isomeric compounds `(A)` and `(B)` are obtained. Monobromination of `(A)` gives several isomeric products of molecular formula `C_(6) H_(3)ClBr_(2)`. While mononbromination of `(B)` yields only two isomers `(C)` and `(D)`. Compound `(C)` is identiacla to one of the compounds obtained from the bromination of `(A)`. However, `(D)` is totally different form any of the isomeric compounds obtained from the bromination of `(A)`. Give the sturctures of `(A),(B),(C)` and `(D)`, and also the structers of the four isomeric mononbrominated products of `(A)`. Support your answer wtih resoning.

Explanation

To solve the problem, we need to identify the structures of the compounds (A), (B), (C), and (D), as well as the four isomeric monobrominated products of (A). Let's break this down step by step.

### Step 1: Identify Compounds (A) and (B)
When bromobenzene is monochlorinated, we can have two isomeric products due to the positions where chlorine can be added relative to the bromine substituent. The two isomers are:
- **(A)**: 2-Bromochlorobenzene (ortho position)
- **(B)**: 4-Bromochlorobenzene (para position)

### Step 2: Monobromination of Compound (A)
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