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A sample of 0.246 gm of an organic compo...

A sample of `0.246 gm` of an organic compound gave `0.198 gm` fo `CO_(2)` and `0.104 gm` of `H_(2)O` on complete combusion. `0.37gm` of the compound gave `0.638 gm` of silver bromide in Carius method. What is the molecular formula of the compound if its molecular mass is `109`.

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To determine the molecular formula of the organic compound based on the provided data, we will follow these steps: ### Step 1: Calculate the moles of carbon from CO₂ Given that 0.198 g of CO₂ is produced, we can calculate the moles of carbon in the compound. 1. **Molar mass of CO₂** = 12 (C) + 16*2 (O) = 44 g/mol 2. **Moles of CO₂** = mass / molar mass = 0.198 g / 44 g/mol = 0.0045 mol 3. Since each mole of CO₂ contains 1 mole of carbon, moles of carbon = 0.0045 mol. ...
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