Consider the following reactions.

Which staements(s) is/are wrong.

Options

A. The product by path `(I)` is `Me - CH = CH_(2) (I)`
B. The product by path `(II)` is `Me - CH (OE) Me (II)`
C. The products are mixture of `(I)` and `(II)` by both paths.
D. Path `I` proceeds cia `E2` mechanism, while path `II` proceeds via `SN^(1)` mechanism.

Answer

`c`

Explanation

Statement (c) is wrong.
i. In path `(I), EtP^(o-)` is a strong base and with `2^(@) RX` groups. The `E2` product predominates over the `SN^(2)` product to give `(Me - CH = CH_(2))`
ii. In path `(II), EtOH` is a weak base, but a better nuclophilc so `SN^(-1)` reaction is favored to give `MeCH(OEt)Me`