300 K पर अभिक्रिया `X_(2)O_(4)(l) to 2XO_(2)(g)` के लिए:
`DeltaU= 2.1 "kcal", DeltaS=20"cal K"^(-1)` है। इसलिए, `DeltaG` है:

Options

A. 9.3 kcal
B. 2.7 kcal
C. `-2.7` kcal
D. `-9.3` kcal

Answer

C

Explanation

`X_(2)O_(4)(l) to 2XO_(2)(g), Deltan_(g) =2-0=2`
`DeltaH =DeltaU +Deltan_(g)RT= 2.1 +2 xx (2)/(1000) xx 300`
`DeltaH =3.3` kcal
`DeltaG=DeltaH -T*DeltaS =3.3 -300 xx (20)/(1000) , DeltaG = -2.7` kcal