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380 mL of a gas at 27^(@) C , 800 mm of ...

380 mL of a gas at `27^(@) C` , 800 mm of Hg weights 0.455 g . The mol., wt. of gas is :

Text Solution

Verified by Experts

Volume of the gas at `NTP= (800 x 380)/(300) xx (273)/(760) mL= 364 mL`
Numbe of moles of the gas `= (364)/(22400).`
Since weight of 1 mole of the gas is numerically equal to mol. Weight, molecular weight `= 0. 455 xx (22400)/(354) = 28.`
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