Balance : `C_(6) H_(5) CHO + Cr_(2)O_(7)^(2-) to C_(6) H_(5) COOH + Cr^(3+)`

Explanation

To balance the redox reaction:

**Step 1: Identify the oxidation and reduction half-reactions.**

The given reaction is:
\[ C_6H_5CHO + Cr_2O_7^{2-} \rightarrow C_6H_5COOH + Cr^{3+} \]

Here, the aldehyde \( C_6H_5CHO \) is oxidized to the carboxylic acid \( C_6H_5COOH \), and the dichromate ion \( Cr_2O_7^{2-} \) is reduced to \( Cr^{3+} \).
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