Balance : `Cu_(2) S + SO_(4)^(2-) to Cu^(2+) + SO_(3)^(2-)` (acidic medium)

Explanation

To balance the redox reaction \( \text{Cu}_2\text{S} + \text{SO}_4^{2-} \rightarrow \text{Cu}^{2+} + \text{SO}_3^{2-} \) in acidic medium, we will follow these steps:

### Step 1: Identify Oxidation States
- In \( \text{Cu}_2\text{S} \):
- Copper (Cu) is in the +1 oxidation state.
- Sulfur (S) is in the -2 oxidation state.
- In \( \text{SO}_4^{2-} \):
- Sulfur (S) is in the +6 oxidation state.
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