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Balance : I(2) to I^(-) + IO(3)^(-) (alk...

Balance : `I_(2) to I^(-) + IO_(3)^(-)` (alkaline medium)

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To balance the reaction \( I_2 \rightarrow I^- + IO_3^- \) in an alkaline medium, we will follow these steps: ### Step 1: Identify the oxidation states - In \( I_2 \), the oxidation state of iodine is 0. - In \( I^- \), the oxidation state of iodine is -1. - In \( IO_3^- \), the oxidation state of iodine is +5. ### Step 2: Write the half-reaction for iodine ...
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RC MUKHERJEE-OXIDATION NUMBER AND BALANCING OF REDOX REACTIONS -PROBLEMS
  1. Balance : I(2) to I^(-) + IO(3)^(-) (alkaline medium)

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  2. C(2) H(5) OH + Cr(2) O(7)^(2-) + H^(+)= Cr^(3+) + C(2) H(4) O + H(2)O

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  3. Sn(OH)(3)^(-) + Bi(OH)(3) + OH^(-) = Sn (OH)(6)^(2-) + Bi

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  4. IO(3)^(-) + N(2) H(4) + HCl= N(2) + I Cl(2)^(-) = N(2) I Cl(2)^(-) + H...

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  5. NO(2) + OH^(-) = NO(3)^(-) + NO(2)^(-) + H(2)O

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  6. Hg(2) Cl(2) + NH(3) = Hg + Hg NH(2) Cl + NH(4) Cl

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  7. Zn + NO(3)^(-) + H^(+) = Zn^(2+) + NH(4)^(+) + H(2)O

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  8. I(2) + NO(3)^(-) + H^(+) = Zn^(2+) + NH(4)^(+) + H(2)O

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  9. MnO(4)^(-) + SO(2)^(2-) + H(2)O = MnO(2) + SO(4)^(2-) + OH^(-)

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  10. H(2) O(2) + ClO(2) + OH^(-) = ClO(2)^(2-) + OH^(-)

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  11. ClO^(-) + CrO(2)^(2-) + OH^(-) = Cl^(-) + CrO(4)^(2-) + H(2)O

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  12. I(2) + Cl(2) + H(2) O = HIO(3) + HCl

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  13. Cl(2) + KOH = KOCl + KCl + H(2)O

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  14. Cl(2) + KOH = KClO(3) + KCl + H(2) O

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  15. H(2) O(2) + I(2) = HIO(3) + H(2)O

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  16. H(2) O(2) + KMnO(4) = MnO(2) + KOH + O(2) + H(2)O

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  17. HNO(2) + KMnO(4) + H(2) SO(4) = HNO(3) + KMnO(4) + K(2) SO(4) + H(2)O

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  18. NaNO(2) + NaI + H(2) SO(4) = NO + I(2) + Na(2) SO(4) + H(2)O

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  19. N(2) H(4) + AgNO(3) + KOH = N(2) + Ag + KNO(3) + H(2) O

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  20. N(2) H(4) + Zn + KOH + H(2) O = NH(3) + K(2) [ Zn (OH)(4)]

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  21. Fe + N(2) H(4) + H(2) O = Fe (OH)(2) + NH(3)

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