Home
Class 12
CHEMISTRY
Balance : P(4) to H(2) PO(2)^(-) + PH(3)...

Balance : `P_(4) to H_(2) PO_(2)^(-) + PH_(3)` (alkaline medium)

Text Solution

AI Generated Solution

To balance the reaction \( P_4 \rightarrow H_2PO_2^- + PH_3 \) in alkaline medium, we will follow these steps: ### Step 1: Assign Oxidation States - In \( P_4 \), phosphorus has an oxidation state of 0. - In \( H_2PO_2^- \), the oxidation state of phosphorus can be calculated as follows: \[ 2 + X + 2(-2) = -1 \implies X - 2 = -1 \implies X = +1 \] ...
Promotional Banner

Topper's Solved these Questions

  • OXIDATION NUMBER AND BALANCING OF REDOX REACTIONS

    RC MUKHERJEE|Exercise PROBLEMS |40 Videos

  • MOLECULAR WEIGHT

    RC MUKHERJEE|Exercise PROBLEMS |12 Videos

  • PROBLEMS BASED ON EQUATIONS: STOICHIOMETRY

    RC MUKHERJEE|Exercise OBJECTIVE PROBLEMS|15 Videos

Similar Questions

Explore conceptually related problems

P_(4)+NaOH to PH_(3) uarr+NaH_(2)PO_(2)

P_(4)+NaOH+H_(2)O rarr NaH_(2)PO_(3)+PH_(3) is

The reaction, P_(4)+3NaOH+3H_(2)O to 3NaH_(2)PO_(2)+PH_(3) is an example of

Balance the following equations: (i) H_(3)PO_(3) to H_(3)PO_(4) + PH_(3) (ii) Ca + H_(2)O to Ca(OH)_(2) + H_(2) (iii) Fe_(2)(SO_(4))_(2) + NH_(3) + H_(2)O to Fe(OH)_(3) + (NH_(4))_(2)SO_(4)

RC MUKHERJEE-OXIDATION NUMBER AND BALANCING OF REDOX REACTIONS -PROBLEMS
  1. Balance : P(4) to H(2) PO(2)^(-) + PH(3) (alkaline medium)

    Text Solution

    |

  2. C(2) H(5) OH + Cr(2) O(7)^(2-) + H^(+)= Cr^(3+) + C(2) H(4) O + H(2)O

    Text Solution

    |

  3. Sn(OH)(3)^(-) + Bi(OH)(3) + OH^(-) = Sn (OH)(6)^(2-) + Bi

    Text Solution

    |

  4. IO(3)^(-) + N(2) H(4) + HCl= N(2) + I Cl(2)^(-) = N(2) I Cl(2)^(-) + H...

    Text Solution

    |

  5. NO(2) + OH^(-) = NO(3)^(-) + NO(2)^(-) + H(2)O

    Text Solution

    |

  6. Hg(2) Cl(2) + NH(3) = Hg + Hg NH(2) Cl + NH(4) Cl

    Text Solution

    |

  7. Zn + NO(3)^(-) + H^(+) = Zn^(2+) + NH(4)^(+) + H(2)O

    Text Solution

    |

  8. I(2) + NO(3)^(-) + H^(+) = Zn^(2+) + NH(4)^(+) + H(2)O

    Text Solution

    |

  9. MnO(4)^(-) + SO(2)^(2-) + H(2)O = MnO(2) + SO(4)^(2-) + OH^(-)

    Text Solution

    |

  10. H(2) O(2) + ClO(2) + OH^(-) = ClO(2)^(2-) + OH^(-)

    Text Solution

    |

  11. ClO^(-) + CrO(2)^(2-) + OH^(-) = Cl^(-) + CrO(4)^(2-) + H(2)O

    Text Solution

    |

  12. I(2) + Cl(2) + H(2) O = HIO(3) + HCl

    Text Solution

    |

  13. Cl(2) + KOH = KOCl + KCl + H(2)O

    Text Solution

    |

  14. Cl(2) + KOH = KClO(3) + KCl + H(2) O

    Text Solution

    |

  15. H(2) O(2) + I(2) = HIO(3) + H(2)O

    Text Solution

    |

  16. H(2) O(2) + KMnO(4) = MnO(2) + KOH + O(2) + H(2)O

    Text Solution

    |

  17. HNO(2) + KMnO(4) + H(2) SO(4) = HNO(3) + KMnO(4) + K(2) SO(4) + H(2)O

    Text Solution

    |

  18. NaNO(2) + NaI + H(2) SO(4) = NO + I(2) + Na(2) SO(4) + H(2)O

    Text Solution

    |

  19. N(2) H(4) + AgNO(3) + KOH = N(2) + Ag + KNO(3) + H(2) O

    Text Solution

    |

  20. N(2) H(4) + Zn + KOH + H(2) O = NH(3) + K(2) [ Zn (OH)(4)]

    Text Solution

    |

  21. Fe + N(2) H(4) + H(2) O = Fe (OH)(2) + NH(3)

    Text Solution

    |