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Balance : NaOH + Al + H(2) O to Na[Al (O...

Balance : `NaOH + Al + H_(2) O to Na[Al (OH)_(4) ] + H_(2)`

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To balance the reaction: **Step 1: Write the unbalanced equation.** The unbalanced equation is: \[ \text{NaOH} + \text{Al} + \text{H}_2\text{O} \rightarrow \text{Na[Al(OH)}_4] + \text{H}_2 \] **Step 2: Identify the oxidation states.** - In NaOH, Na is +1, O is -2, and H is +1. ...
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RC MUKHERJEE-OXIDATION NUMBER AND BALANCING OF REDOX REACTIONS -PROBLEMS
  1. Balance : NaOH + Al + H(2) O to Na[Al (OH)(4) ] + H(2)

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  2. C(2) H(5) OH + Cr(2) O(7)^(2-) + H^(+)= Cr^(3+) + C(2) H(4) O + H(2)O

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  3. Sn(OH)(3)^(-) + Bi(OH)(3) + OH^(-) = Sn (OH)(6)^(2-) + Bi

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  4. IO(3)^(-) + N(2) H(4) + HCl= N(2) + I Cl(2)^(-) = N(2) I Cl(2)^(-) + H...

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  5. NO(2) + OH^(-) = NO(3)^(-) + NO(2)^(-) + H(2)O

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  6. Hg(2) Cl(2) + NH(3) = Hg + Hg NH(2) Cl + NH(4) Cl

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  7. Zn + NO(3)^(-) + H^(+) = Zn^(2+) + NH(4)^(+) + H(2)O

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  8. I(2) + NO(3)^(-) + H^(+) = Zn^(2+) + NH(4)^(+) + H(2)O

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  9. MnO(4)^(-) + SO(2)^(2-) + H(2)O = MnO(2) + SO(4)^(2-) + OH^(-)

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  10. H(2) O(2) + ClO(2) + OH^(-) = ClO(2)^(2-) + OH^(-)

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  11. ClO^(-) + CrO(2)^(2-) + OH^(-) = Cl^(-) + CrO(4)^(2-) + H(2)O

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  12. I(2) + Cl(2) + H(2) O = HIO(3) + HCl

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  13. Cl(2) + KOH = KOCl + KCl + H(2)O

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  14. Cl(2) + KOH = KClO(3) + KCl + H(2) O

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  15. H(2) O(2) + I(2) = HIO(3) + H(2)O

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  16. H(2) O(2) + KMnO(4) = MnO(2) + KOH + O(2) + H(2)O

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  17. HNO(2) + KMnO(4) + H(2) SO(4) = HNO(3) + KMnO(4) + K(2) SO(4) + H(2)O

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  18. NaNO(2) + NaI + H(2) SO(4) = NO + I(2) + Na(2) SO(4) + H(2)O

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  19. N(2) H(4) + AgNO(3) + KOH = N(2) + Ag + KNO(3) + H(2) O

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  20. N(2) H(4) + Zn + KOH + H(2) O = NH(3) + K(2) [ Zn (OH)(4)]

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  21. Fe + N(2) H(4) + H(2) O = Fe (OH)(2) + NH(3)

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