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Balance : C(2) H(5) OH + O(2) to CO(2) +...

Balance : `C_(2) H_(5) OH + O_(2) to CO_(2) + H_(2)O`

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To balance the chemical equation for the combustion of ethanol (\(C_2H_5OH\)), we will follow these steps: ### Step 1: Write the unbalanced equation The unbalanced equation is: \[ C_2H_5OH + O_2 \rightarrow CO_2 + H_2O \] ### Step 2: Count the number of atoms of each element on both sides - **Reactants:** ...
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The enthalpy of formation of C_(2)H_(5)OH(l) , CO_(2)(g) and H_(2)O(l) are - 277.0, -393.5 and -285.5 kJ/mol respectively.Calculate the enthalpy change for the reaction: C_(2)H_(5)OH(l) + 3O_(2)(g) to 2CO_(2)(g) + 3H_(2)O(l) .

Given that : C(s)+O_(2)(g)to CO_(2)(g) , Delta H = -394 kJ and 2H_(2)(g)+O_(2)(g)to 2H_(2)O(l) , Delta H =- 568 kJ and C_(2)H_(5)OH(l)+3O_(2)(g)to 2CO_(2)(g)+3H_(2)O(l) , Delta H =- 1058 kJ/mole. Using the data, the heat of formation of ethanol is

If one mole of ethanol (C_(2)H_(5)OH) completely burns to form carbon dioxide and water, the weight of carbon dioxide formed is about – C_(2)H_(5)OH+3O_(2) rarr 2CO_(2)+3H_(2)O

Find the heat of formation of ethyl alcohol for following data C(s) +O_(2)(g) rarr CO_(2)(g) DeltaH =- 94 kcal H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l), DeltaH =- 68 kcal C_(2)H_(5)OH(l)+3O_(2)(g) rarr 2CO_(2)(g) +3H_(2)O(l) DeltaH =- 327 kcal

Balance the following equations by hit and trial method: (a) KMnO_(4) + HCl to KCl + MnCl_(2) + H_(2)O + Cl_(2) (b) H_(2)S + SO_(2) to S + H_(2)O ( c) K_(2)Cr_(2)O_(7) + H_(2)SO_(4) to K_(2)SO_(4) + Cr_(2)(SO_(4))_(2) + H_(2)O + O_(2) (d) KMnO_(4) + KOH to K_(2)MnO_(4) + O_(2) + H_(2)O (e) Mg_(3)N_(2) + H_(2)O to Mg(OH)_(2) + NH_(3) (f) Al_(4)C_(3) + H_(2)O to Al(OH)_(3) + CH_(4) (g) FeS_(2) + O_(2) to Fe_(2)O_(3) + SO_(2) (h) KMnO_(4) + H_(2)S + H_(2)SO_(4) to KHSO_(4) + MnSO_(4) + S + H_(2)O (i) C_(3)H_(8)(g) + O_(2)(g) to CO_(2)(g) + H_(2)O(l)

RC MUKHERJEE-OXIDATION NUMBER AND BALANCING OF REDOX REACTIONS -PROBLEMS
  1. Balance : C(2) H(5) OH + O(2) to CO(2) + H(2)O

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  2. C(2) H(5) OH + Cr(2) O(7)^(2-) + H^(+)= Cr^(3+) + C(2) H(4) O + H(2)O

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  3. Sn(OH)(3)^(-) + Bi(OH)(3) + OH^(-) = Sn (OH)(6)^(2-) + Bi

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  4. IO(3)^(-) + N(2) H(4) + HCl= N(2) + I Cl(2)^(-) = N(2) I Cl(2)^(-) + H...

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  5. NO(2) + OH^(-) = NO(3)^(-) + NO(2)^(-) + H(2)O

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  6. Hg(2) Cl(2) + NH(3) = Hg + Hg NH(2) Cl + NH(4) Cl

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  7. Zn + NO(3)^(-) + H^(+) = Zn^(2+) + NH(4)^(+) + H(2)O

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  8. I(2) + NO(3)^(-) + H^(+) = Zn^(2+) + NH(4)^(+) + H(2)O

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  9. MnO(4)^(-) + SO(2)^(2-) + H(2)O = MnO(2) + SO(4)^(2-) + OH^(-)

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  10. H(2) O(2) + ClO(2) + OH^(-) = ClO(2)^(2-) + OH^(-)

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  11. ClO^(-) + CrO(2)^(2-) + OH^(-) = Cl^(-) + CrO(4)^(2-) + H(2)O

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  12. I(2) + Cl(2) + H(2) O = HIO(3) + HCl

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  13. Cl(2) + KOH = KOCl + KCl + H(2)O

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  14. Cl(2) + KOH = KClO(3) + KCl + H(2) O

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  15. H(2) O(2) + I(2) = HIO(3) + H(2)O

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  16. H(2) O(2) + KMnO(4) = MnO(2) + KOH + O(2) + H(2)O

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  17. HNO(2) + KMnO(4) + H(2) SO(4) = HNO(3) + KMnO(4) + K(2) SO(4) + H(2)O

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  18. NaNO(2) + NaI + H(2) SO(4) = NO + I(2) + Na(2) SO(4) + H(2)O

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  19. N(2) H(4) + AgNO(3) + KOH = N(2) + Ag + KNO(3) + H(2) O

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  20. N(2) H(4) + Zn + KOH + H(2) O = NH(3) + K(2) [ Zn (OH)(4)]

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  21. Fe + N(2) H(4) + H(2) O = Fe (OH)(2) + NH(3)

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