H(2) O(2) + I(2) = HIO(3) + H(2)O...

`H_(2) O_(2) + I_(2) = HIO_(3) + H_(2)O`

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To balance the redox reaction \( H_2O_2 + I_2 \rightarrow HIO_3 + H_2O \), we will follow a systematic approach to identify the oxidation states, determine the changes, and balance the equation. ### Step 1: Assign Oxidation States - In \( H_2O_2 \) (hydrogen peroxide), the oxidation state of oxygen is \(-1\). - In \( I_2 \) (iodine), the oxidation state of iodine is \(0\). - In \( HIO_3 \) (iodic acid), the oxidation state of iodine is \(+5\). - In \( H_2O \) (water), the oxidation state of oxygen is \(-2\). ...

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RC MUKHERJEE-OXIDATION NUMBER AND BALANCING OF REDOX REACTIONS -PROBLEMS

Cl(2) + KOH = KOCl + KCl + H(2)O
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Cl(2) + KOH = KClO(3) + KCl + H(2) O
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H(2) O(2) + I(2) = HIO(3) + H(2)O
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H(2) O(2) + KMnO(4) = MnO(2) + KOH + O(2) + H(2)O
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HNO(2) + KMnO(4) + H(2) SO(4) = HNO(3) + KMnO(4) + K(2) SO(4) + H(2)O
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NaNO(2) + NaI + H(2) SO(4) = NO + I(2) + Na(2) SO(4) + H(2)O
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N(2) H(4) + AgNO(3) + KOH = N(2) + Ag + KNO(3) + H(2) O
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N(2) H(4) + Zn + KOH + H(2) O = NH(3) + K(2) [ Zn (OH)(4)]
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Fe + N(2) H(4) + H(2) O = Fe (OH)(2) + NH(3)
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H(2) S + HNO(3) = NO + S + H(2) O
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Balance the chemical equation by the oxidation number method. (ii) ...
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Balance the following equation by oxidation number method K(2)Cr(2)O...
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MnO(4)^(-) + C(2) O(4)^(2-) + H^(+) = CO(2) + Mn^(2+) + H(2) O
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Cr(2) O(7)^(2-) + C(2) O(4)^(2-) + H^(+) = Cr^(3+) + CO(2) + H(2) O
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Cr(OH)(3) + IO(3) + OH^(-) = I^(-) + CrO(4)^(2-) + H(2)O
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KMnO(4) overset(Delta) to K(2)MnO(4)+MnO(2)+O(2)uarr
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(NH(4))(2) Cr(2)O(7) = N(2) + H(2) O + Cr(2) O(3)
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MnO(4)^(2-) + H^(+) = MnO(4)^(-) + MnO(2) + H(2) O
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H(3) PO(3) = H(3) PO(4) + PH(3)
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Zn + HNO(3) = Zn (NO(3))(2) + N(2) O + H(2) O
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