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Cr(OH)(3) + IO(3) + OH^(-) = I^(-) + CrO...

`Cr(OH)_(3) + IO_(3) + OH^(-) = I^(-) + CrO_(4)^(2-) + H_(2)O`

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To balance the redox reaction given by the equation: \[ \text{Cr(OH)}_3 + \text{IO}_3^- + \text{OH}^- \rightarrow \text{I}^- + \text{CrO}_4^{2-} + \text{H}_2\text{O} \] we will follow these steps: ### Step 1: Assign Oxidation States First, we need to assign oxidation states to all elements in the reaction to identify which species are oxidized and which are reduced. ...
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In the following reaction: Cr(OH)_(3)+OH^(-)+IO_(3)^(-) toCrO_(4)^(2-)+H_(2)O+I^(-)