Zn + HNO(3) = Zn (NO(3))(2) + N(2) O + H...

`Zn + HNO_(3) = Zn (NO_(3))_(2) + N_(2) O + H_(2) O `

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To balance the redox reaction of zinc and nitric acid, we will follow these steps: ### Step 1: Write the unbalanced equation The unbalanced equation is: \[ \text{Zn} + \text{HNO}_3 \rightarrow \text{Zn(NO}_3\text{)}_2 + \text{N}_2\text{O} + \text{H}_2\text{O} \] ### Step 2: Assign oxidation states - **Zinc (Zn)**: 0 (elemental state) ...

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RC MUKHERJEE-OXIDATION NUMBER AND BALANCING OF REDOX REACTIONS -PROBLEMS

H(2) S + HNO(3) = NO + S + H(2) O
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Balance the chemical equation by the oxidation number method. (ii) ...
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Balance the following equation by oxidation number method K(2)Cr(2)O...
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MnO(4)^(-) + C(2) O(4)^(2-) + H^(+) = CO(2) + Mn^(2+) + H(2) O
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Cr(2) O(7)^(2-) + C(2) O(4)^(2-) + H^(+) = Cr^(3+) + CO(2) + H(2) O
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Cr(OH)(3) + IO(3) + OH^(-) = I^(-) + CrO(4)^(2-) + H(2)O
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KMnO(4) overset(Delta) to K(2)MnO(4)+MnO(2)+O(2)uarr
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(NH(4))(2) Cr(2)O(7) = N(2) + H(2) O + Cr(2) O(3)
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MnO(4)^(2-) + H^(+) = MnO(4)^(-) + MnO(2) + H(2) O
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H(3) PO(3) = H(3) PO(4) + PH(3)
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Zn + HNO(3) = Zn (NO(3))(2) + N(2) O + H(2) O
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CuS + NO(3)^(-) + H^(+)= Cu^(2+) + S(8) + NO + H(2) O
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CuSO(4) + KI = Cu(2) I(2) + I(2) + K(2) SO(4)
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FeSO(4) = Fe(2) O(3) + SO(2) + SO(3)
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NaOH + Cl(2) NaCl + NaClO + H(2) O
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NH(3) + Hg(2) Cl(2) = Hg + Hg (NH(2)) Cl + HCl
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Br + OH^(-) = BrO^(-) + Br^(-) + H(2) O
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As(2) S(5) + HNO(3) = H(2) SO(4) + NO(2)+ H(3) AsO(4) + H(2) O
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Cr(2) O(7)^(2-) + SO(2) + H^(+) = Cr^(3+) + HSO(4)^(-) + H(2) O
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HCl + WO(3) + SnCl(2) = H(2) SnCl(6) + W(3) O(8) + H(2) O
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