As(2) S(5) + HNO(3) = H(2) SO(4) + NO(2)...

`As_(2) S_(5) + HNO_(3) = H_(2) SO_(4) + NO_(2)+ H_(3) AsO_(4) + H_(2) O `

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To balance the given redox reaction \( \text{As}_2\text{S}_5 + \text{HNO}_3 \rightarrow \text{H}_2\text{SO}_4 + \text{NO}_2 + \text{H}_3\text{AsO}_4 + \text{H}_2\text{O} \), we will follow these steps: ### Step 1: Determine Oxidation States - In \( \text{As}_2\text{S}_5 \), arsenic (As) has an oxidation state of -2, and sulfur (S) has an oxidation state of +2. - In \( \text{H}_2\text{SO}_4 \), sulfur has an oxidation state of +6. - In \( \text{H}_3\text{AsO}_4 \), arsenic has an oxidation state of +5. - In \( \text{HNO}_3 \), nitrogen (N) has an oxidation state of +5, and in \( \text{NO}_2 \), it has an oxidation state of +4. ...

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RC MUKHERJEE-OXIDATION NUMBER AND BALANCING OF REDOX REACTIONS -PROBLEMS

H(2) S + HNO(3) = NO + S + H(2) O
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Balance the chemical equation by the oxidation number method. (ii) ...
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Balance the following equation by oxidation number method K(2)Cr(2)O...
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MnO(4)^(-) + C(2) O(4)^(2-) + H^(+) = CO(2) + Mn^(2+) + H(2) O
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Cr(2) O(7)^(2-) + C(2) O(4)^(2-) + H^(+) = Cr^(3+) + CO(2) + H(2) O
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Cr(OH)(3) + IO(3) + OH^(-) = I^(-) + CrO(4)^(2-) + H(2)O
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(NH(4))(2) Cr(2)O(7) = N(2) + H(2) O + Cr(2) O(3)
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MnO(4)^(2-) + H^(+) = MnO(4)^(-) + MnO(2) + H(2) O
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H(3) PO(3) = H(3) PO(4) + PH(3)
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Zn + HNO(3) = Zn (NO(3))(2) + N(2) O + H(2) O
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CuS + NO(3)^(-) + H^(+)= Cu^(2+) + S(8) + NO + H(2) O
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CuSO(4) + KI = Cu(2) I(2) + I(2) + K(2) SO(4)
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FeSO(4) = Fe(2) O(3) + SO(2) + SO(3)
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NaOH + Cl(2) NaCl + NaClO + H(2) O
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NH(3) + Hg(2) Cl(2) = Hg + Hg (NH(2)) Cl + HCl
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Br + OH^(-) = BrO^(-) + Br^(-) + H(2) O
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As(2) S(5) + HNO(3) = H(2) SO(4) + NO(2)+ H(3) AsO(4) + H(2) O
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Cr(2) O(7)^(2-) + SO(2) + H^(+) = Cr^(3+) + HSO(4)^(-) + H(2) O
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HCl + WO(3) + SnCl(2) = H(2) SnCl(6) + W(3) O(8) + H(2) O
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