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Cr(2) O(7)^(2-) + SO(2) + H^(+) = Cr^(3+...

`Cr_(2) O_(7)^(2-) + SO_(2) + H^(+) = Cr^(3+) + HSO_(4)^(-) + H_(2) O `

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To balance the redox reaction given by: \[ \text{Cr}_2\text{O}_7^{2-} + \text{SO}_2 + \text{H}^+ \rightarrow \text{Cr}^{3+} + \text{HSO}_4^{-} + \text{H}_2\text{O} \] we will follow these steps: ### Step 1: Identify Oxidation States - In \(\text{Cr}_2\text{O}_7^{2-}\), the oxidation state of Cr is +6. ...
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For the following redox reaction the coefficients of the reactants for balanced reaction are Cr_2O_7^(2-) + SO_3^(2-) + H^+ rarr Cr^(3+) + SO_4^(2-) + H_2O

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