HCl + WO(3) + SnCl(2) = H(2) SnCl(6) + W...

`HCl + WO_(3) + SnCl_(2) = H_(2) SnCl_(6) + W_(3) O_(8) + H_(2) O `

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To balance the given redox reaction: **Unbalanced Reaction:** \[ \text{HCl} + \text{WO}_3 + \text{SnCl}_2 \rightarrow \text{H}_2\text{SnCl}_6 + \text{W}_3\text{O}_8 + \text{H}_2\text{O} \] ### Step 1: Identify Oxidation States - In \( \text{WO}_3 \), the oxidation state of W is +6. - In \( \text{SnCl}_2 \), the oxidation state of Sn is +2. ...

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Give the decreasing order of covalent character of the following compounds. a. I. GeCl_(2) II. GeCl_(4) III. SnCl_(2) IV. SnCl_(4) V. PbCl_(2) VI. PbCl_(4) b. I. CH_(4) II. NH_(3) III. H_(2)O IV. HF c. I. HF II. HCl III. HBr IV. HI d. I. AgI II. NaI III. CuI IV. NaCl

Consider the following reactions, (I) 2Mn_(2)O_(7) rarr 4MnO_(2) + 3O_(2) (II) SnCl_(2) + 2FeCl_(3) rarr SnCl_(4) + 2FeCl_(2)

On the basis of following data , Evaluate the standard enthalpy of formation of tungsten carbide (WC) (i) W(s) + (3)/(2) O_(2) (g) to WO_(3) (s) Delta_(r) H^(@) = -837 kJ/mol (ii) WC(s) + (5)/(2) O_(2) (g) to WO_(3) (s) + CO_(2) (g) Delta_(r) H^(@) = -1196 kJ/mol (iii) C(graphite) + O_(2) (g) to CO_(2) (g) Delta H^(@) = -393.5 kJ/mol

Name the following boric acids: a. H_(3)BO_(3) or B_(2)O_(3).3H_(2)O b. HBO_(2) or B_(2)O_(3).H_(2)O c. H_(2)B_(4)O_(7) or 2B_(2)O_(3).H_(2)O d. H_(6)B_(4)O_(9) or 2B_(2)O_(3).3H_(2)O

Consider the following reactions: (i) PCl_(3)+3H_(2)O to H_(3)PO_(3) +3HCl (ii) SF_(4)+3H_(2)O to H_(3)SO_(3)+4HF (iii) BCl_(3)+3H_(2)O to H_(3)BO_(3)+3HCl (iv) XeF_(6)+3H_(2)O to XeO_(3)+6HF Then according to given information the incorrect statement is:

RC MUKHERJEE-OXIDATION NUMBER AND BALANCING OF REDOX REACTIONS -PROBLEMS

H(2) S + HNO(3) = NO + S + H(2) O
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Balance the chemical equation by the oxidation number method. (ii) ...
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Balance the following equation by oxidation number method K(2)Cr(2)O...
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MnO(4)^(-) + C(2) O(4)^(2-) + H^(+) = CO(2) + Mn^(2+) + H(2) O
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Cr(2) O(7)^(2-) + C(2) O(4)^(2-) + H^(+) = Cr^(3+) + CO(2) + H(2) O
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Cr(OH)(3) + IO(3) + OH^(-) = I^(-) + CrO(4)^(2-) + H(2)O
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KMnO(4) overset(Delta) to K(2)MnO(4)+MnO(2)+O(2)uarr
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(NH(4))(2) Cr(2)O(7) = N(2) + H(2) O + Cr(2) O(3)
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MnO(4)^(2-) + H^(+) = MnO(4)^(-) + MnO(2) + H(2) O
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H(3) PO(3) = H(3) PO(4) + PH(3)
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Zn + HNO(3) = Zn (NO(3))(2) + N(2) O + H(2) O
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CuS + NO(3)^(-) + H^(+)= Cu^(2+) + S(8) + NO + H(2) O
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CuSO(4) + KI = Cu(2) I(2) + I(2) + K(2) SO(4)
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FeSO(4) = Fe(2) O(3) + SO(2) + SO(3)
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NaOH + Cl(2) NaCl + NaClO + H(2) O
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NH(3) + Hg(2) Cl(2) = Hg + Hg (NH(2)) Cl + HCl
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Br + OH^(-) = BrO^(-) + Br^(-) + H(2) O
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As(2) S(5) + HNO(3) = H(2) SO(4) + NO(2)+ H(3) AsO(4) + H(2) O
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Cr(2) O(7)^(2-) + SO(2) + H^(+) = Cr^(3+) + HSO(4)^(-) + H(2) O
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HCl + WO(3) + SnCl(2) = H(2) SnCl(6) + W(3) O(8) + H(2) O
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