A rocket is launched vertically from the surface of the earth with an initial velocity of 10km/s .How far above the earth would it go?Radius of earth =6400kkm.

At what height above the surface of the earth will the acceleration due to gravity be half of its value on the earth's surface ? Radius of the earth =6400 km.

An artificial satellite is moving in an orbit around the earth with a velocity equal to one-third the escape velocity from the surface of the earth. (ii) The satellite comes to rest in its orbit and then is allowed to fall freely on to the surface of the earth. Find the speed with which the satellite strikes the earth's surface. Given radius of earth =6400 km.

A body hanging from a spring stretches it by 1 cm at the earth's surface.How much will the same body stretch the spring at a place 1600 km above the earth's surface? Radius of earth =6400km.

At what height above the surface of earth acceleration due to gravity will be (ii) 50% of its value on the surface of the earth. Given radius of earth =6400 km.

An artificial satellite revolves around the earth in a circular orbit and is at a height of 300 km above the surface of the earth. Find the orbital speed and the time period of the satellite. The radius of the earth=6400 km, g=980 cm*s^(-2) .