The pitch of a screw gauge is 1 mm & there are 100 division on the circular scale. In measuring the diameter of a sphere there are six divisions on the linear scale & forty divisions on circular scale coincides with the reference line. Find the diameter of the sphere.

A screw gauge of pitch 1.0 mm has 200 divisions on its circular scale. Find out its least count.

Find the screw pitch of a screw gauge having 100 circular scale divisions and a least count of 0.002 cm.

When the diameter of a wire is measured by a screw gauge the main scale and the circular scale readings are 0 mm and 52 respectively. Given screw pitch = 1mm and number of divisions on the circular scale = 100. Find out the diameter of the wire.

The circular scale of screw gauge after two complete rotations advances 1 mm along the linear scale. The circular scale has 50 equal divisions and the mechanical error of the screw gauge is -0.03 mm . The linear scale reading =3 mm and the circular scale reading =35 when a student attempts to measure the diameter of a wire. Calculate the diameter from the given data.

A student performs an experiment of measuring the thickness of a slab with a vernier calliper whose 50 divisions of the vernier scale are equal to 49 divisions of the main scale. He noted that zero of the vernier scale is between 7.00 cm and 7.05 cm mark of the main scale and 23rd division of the vernier scale exactly coninides with the scale. the measured value of the thickness of the given slab using the calliper will be

Pitch of a screw gauze instrument is 0.5 mm and its circular scale is divided into 100 divisions. The least count of the instrument will be