tan^(-1)1+"tan"^(-1)1/3=?...

`tan^(-1)1+"tan"^(-1)1/3=?`

`tan^(-1)2`

`tan^(-1)3`

`"tan"^(-1)4/3`

`"tan"^(-1)2/3`

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The correct Answer is:

cos^(-1)(cos""(7pi)/(6)) का मान बराबर है
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cot(tan^(-1)x+cot^(-1)x)=?
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tan^(-1)1+"tan"^(-1)1/3=?
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tan^(-1)x+cot^(-1)x=?
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"sin"^(-1)1/x=?
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यदि -1ltxlt1, तो 2tan^(-1)x=?
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cos^(-1)((-1)/2)=
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3"sec"^(-1)1/x-sin^(-1)(4x^(3)-3x)=
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"tan^(-1)(4sqrt(x))/(2-2x)=
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cot^(-1)(-x) का मान बराबर है-
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cos^(-1)(2x-1)=
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2cot^(-1)3+cot^(-1)7=
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cos^(-1)("cos"(8pi)/5)=
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tan^(-1)(1)+cos^(-1)(-(1)/(2))+sin^(-1)(-(1)/(2)) का मान ज्ञात कीजिए।
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tan^(-1)x +cot^(-1)x का मान है
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sec^(2)(tan^(-1)5)+cosec^(2)(cot^(-1)5)=
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"tan"^(-1)1/2+"tan"^(-1)1/3=
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sin("sin"^(-1)1/2+"cos"^(-1)1/2)=
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tan^(-1)(1)=………….?
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tan^(-1)x+cot^(-1)x=.
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