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In a certain region, vec(B) increases ra...

In a certain region, `vec(B)` increases radially as `vec(E)=90 r(-hat(r))`. The magnitude of electric charge (in `mu C` ) contained within-a sphere of radius `2 m` centered at the origin is.

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To find the magnitude of electric charge contained within a sphere of radius 2 m centered at the origin, we will follow these steps: ### Step 1: Understand the Electric Field The electric field is given as: \[ \vec{E} = 90r \hat{r} \] This indicates that the electric field increases radially outward with a magnitude proportional to the distance \( r \). ### Step 2: Relate Electric Field to Charge Density From Gauss's law, we know that the electric field \( \vec{E} \) is related to the charge density \( \rho \) by the equation: \[ \vec{E} = \frac{\rho}{3 \epsilon_0} \hat{r} \] where \( \epsilon_0 \) is the permittivity of free space. ### Step 3: Set Up the Equation Equating the two expressions for the electric field: \[ 90r \hat{r} = \frac{\rho}{3 \epsilon_0} \hat{r} \] This implies: \[ \rho = 270 \epsilon_0 \] ### Step 4: Calculate the Charge Density Using the value of \( \epsilon_0 \): \[ \epsilon_0 \approx 8.85 \times 10^{-12} \, \text{C}^2/\text{N m}^2 \] Thus, \[ \rho = 270 \times 8.85 \times 10^{-12} \approx 2.39 \times 10^{-9} \, \text{C/m}^3 \] ### Step 5: Calculate the Volume of the Sphere The volume \( V \) of a sphere of radius \( r = 2 \, \text{m} \) is given by: \[ V = \frac{4}{3} \pi r^3 = \frac{4}{3} \pi (2)^3 = \frac{4}{3} \pi (8) = \frac{32}{3} \pi \, \text{m}^3 \] ### Step 6: Calculate the Total Charge The total charge \( Q \) contained within the sphere can be calculated using: \[ Q = \rho \cdot V \] Substituting the values: \[ Q = (2.39 \times 10^{-9} \, \text{C/m}^3) \cdot \left(\frac{32}{3} \pi \, \text{m}^3\right) \] Calculating the volume: \[ V \approx 33.51 \, \text{m}^3 \] Thus, \[ Q \approx 2.39 \times 10^{-9} \cdot 33.51 \approx 8.01 \times 10^{-8} \, \text{C} \] ### Step 7: Convert to Microcoulombs To convert to microcoulombs: \[ Q \approx 8.01 \times 10^{-8} \, \text{C} = 0.0801 \, \mu C \] ### Final Answer The magnitude of electric charge contained within the sphere of radius 2 m is approximately: \[ \boxed{0.08 \, \mu C} \]
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