A power transformer is used to step-up an slternating emf of `220 V` toll `(kV)` to transmit `4.4 kW` of power. If the primary coil has 1000 tums, what is the curtent (in ampere) in the secondary?

Answer

To solve the problem, we need to find the current in the secondary coil of a power transformer. We are given the following information:

- Primary voltage (Vp) = 220 V
- Secondary voltage (Vs) = 4.4 kV = 4400 V
- Power transmitted (Ps) = 4.4 kW = 4400 W
- Number of turns in the primary coil (Np) = 1000 turns

### Step-by-Step Solution:

1. **Understand the Transformer Relations:**
The transformer operates on the principle of electromagnetic induction, and the relationship between the primary and secondary voltages and turns is given by:
\[ \frac{V_p}{V_s} = \frac{N_p}{N_s} \]
where \(N_s\) is the number of turns in the secondary coil.

2. **Calculate the Secondary Voltage:**
We know the secondary voltage \(Vs\) is given as 4.4 kV, which is equal to 4400 V.

3. **Calculate the Power in the Secondary:**
The power in the secondary coil is given as \(Ps = 4.4 kW = 4400 W\).

4. **Use the Power Formula:**
The power in the secondary coil can also be expressed as:
\[ P_s = V_s \cdot I_s \]
where \(I_s\) is the current in the secondary coil.

5. **Rearranging the Power Formula:**
To find the current in the secondary coil, rearrange the formula:
\[ I_s = \frac{P_s}{V_s} \]

6. **Substituting the Values:**
Now, substitute the known values into the equation:
\[ I_s = \frac{4400 W}{4400 V} \]

7. **Calculate the Current:**
\[ I_s = 1 A \]

### Final Answer:
The current in the secondary coil is \(1 A\).

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