What will be the amount of DNA in meiosis-II products if meiocyte contains 30 pg DNA is `G_(1)` - phase ?

Options

A. 30 pg
B. 60 pg
C. 15 pg
D. 120 pg

Answer

To determine the amount of DNA in the products of meiosis II when the meiocyte contains 30 pg of DNA in the G1 phase, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the DNA content in G1 phase**:
- The meiocyte has 30 picograms (pg) of DNA in the G1 phase. This is the initial amount before any replication occurs.

2. **Understand the S phase**:
- After the G1 phase, the cell enters the S phase (synthesis phase), where DNA replication occurs. During this phase, the amount of DNA doubles.
- Therefore, the amount of DNA after the S phase will be:
\[ 30 \, \text{pg} \times 2 = 60 \, \text{pg} \]

3. **Meiosis I**:
- In meiosis I, the cell divides into two daughter cells. Each daughter cell will receive half of the total DNA content.
- Thus, after meiosis I, each daughter cell will have:
\[ \frac{60 \, \text{pg}}{2} = 30 \, \text{pg} \]

4. **Meiosis II**:
- Meiosis II is similar to mitosis, where the two daughter cells from meiosis I will divide again. However, this division does not involve DNA replication.
- Each of the two daughter cells from meiosis I will divide into two, resulting in four haploid cells.
- Since each daughter cell has 30 pg of DNA, after meiosis II, the amount of DNA in each of the four haploid cells will be:
\[ \frac{30 \, \text{pg}}{2} = 15 \, \text{pg} \]

5. **Final Result**:
- Therefore, the amount of DNA in each of the four products of meiosis II will be 15 pg.

### Conclusion:
The amount of DNA in the products of meiosis II will be **15 pg** in each of the four haploid cells formed.

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