Comparing small and large cells, which statement is correct ?
(1) Small cells have a small surface area per cells
(2) Exchange rate of nutrients is fast with large cells
(3) Small cells have a large surface area per volume ratio
(4) Exchange rate of nutrients is slow with small cells

Options

A. `G_(1)` phase
B. Prophase of mitosis
C. S-phase
D. `G_(2)` phase

Answer

To solve the question regarding the comparison between small and large cells, we need to analyze each statement provided:

1. **Small cells have a small surface area per cell.**
- This statement is incorrect. Small cells actually have a relatively larger surface area compared to their volume. Since the volume of a small cell is less, the surface area to volume ratio is higher.

2. **Exchange rate of nutrients is fast with large cells.**
- This statement is also incorrect. In large cells, the exchange of nutrients is slower because the volume of cytoplasm is greater compared to the size of the nucleus. This means that it takes longer for nutrients to diffuse throughout the larger volume of the cell.

3. **Small cells have a large surface area per volume ratio.**
- This statement is correct. Small cells have a higher surface area to volume ratio, which facilitates more efficient exchange of materials (nutrients, waste) with their environment.

4. **Exchange rate of nutrients is slow with small cells.**
- This statement is incorrect. Small cells can exchange nutrients more quickly due to their larger surface area relative to their volume, allowing for faster diffusion of materials.

### Conclusion:
The correct statement is **(3) Small cells have a large surface area per volume ratio.**