Repolarisation of the axonal membrane results in development of

Options

A. Negative charge on the outer side and positive charge on the inner side
B. Positive charge on the outer side and negative charge on the inner side
C. Negative charge on both the sides
D. Positive charge on both the sides

Answer

### Step-by-Step Solution:

1. **Understanding the Resting State**:
- In the resting state, the axonal membrane is polarized. The inner side (axoplasm) has a negative charge, while the outer side has a positive charge. This is primarily due to the activity of the sodium-potassium pump, which moves 3 sodium ions (Na+) out of the cell and 2 potassium ions (K+) into the cell.

2. **Membrane Potential**:
- The resting membrane potential is approximately -70 mV. This indicates that the inside of the neuron is negatively charged relative to the outside.

3. **Depolarization Phase**:
- When a stimulus occurs, sodium channels open, allowing Na+ ions to rush into the neuron. This influx of positive charge causes the inner side of the membrane to become positively charged, while the outer side becomes negatively charged.

4. **Repolarization Phase**:
- After depolarization, the sodium channels close, and the sodium-potassium pump becomes active again. It pumps 3 Na+ ions out of the cell and 2 K+ ions back in. This process restores the negative charge on the inner side and the positive charge on the outer side of the membrane.

5. **Final Charge Distribution**:
- During repolarization, the inner side of the membrane becomes negatively charged, and the outer side becomes positively charged, returning the membrane to its resting state and preparing it for the next action potential.

### Conclusion:
- The repolarization of the axonal membrane results in the development of a **negative charge on the inner side** and a **positive charge on the outer side** of the membrane.