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Choose the correct pair regarding ionisa...

Choose the correct pair regarding ionisation energy `(IE_(1))`

A

`B gt Be`

B

`Tl gt Ga`

C

`N gt O`

D

`Li gt Na`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the correct pair of ionization energy (IE₁), we will analyze each option step by step. ### Step 1: Understanding Ionization Energy **Definition**: Ionization energy is the energy required to remove an electron from the outermost shell of an isolated gaseous atom. ### Step 2: Analyzing Each Option 1. **Option 1: Boron (B) has greater ionization energy than Beryllium (Be)** - Atomic number of Beryllium (Be) = 4; Electronic configuration: 1s² 2s² - Atomic number of Boron (B) = 5; Electronic configuration: 1s² 2s² 2p¹ - **Comparison**: The penetration power of the s orbital is greater than that of the p orbital. Therefore, it is easier to remove an electron from Boron than from Beryllium. - **Conclusion**: This option is **incorrect**. 2. **Option 2: Thallium (Tl) has greater ionization energy than Gallium (Ga)** - Both elements belong to group 13 of the periodic table. - **D-block contraction**: The presence of d-orbitals in the transition metals affects the ionization energy. Thallium experiences additional contraction due to the presence of f-block elements (actinoid contraction). - **Conclusion**: Thallium has a greater ionization energy than Gallium due to these contractions. This option is **correct**. 3. **Option 3: Nitrogen (N) has greater ionization energy than Oxygen (O)** - Atomic number of Nitrogen (N) = 7; Electronic configuration: 1s² 2s² 2p³ - Atomic number of Oxygen (O) = 8; Electronic configuration: 1s² 2s² 2p⁴ - **Comparison**: Nitrogen has a half-filled p subshell (2p³), which is more stable than the partially filled subshell of Oxygen (2p⁴). Thus, it requires more energy to remove an electron from Nitrogen. - **Conclusion**: This option is **correct**. 4. **Option 4: Lithium (Li) has greater ionization energy than Sodium (Na)** - Atomic number of Lithium (Li) = 3; Atomic number of Sodium (Na) = 11. - **Trend**: Ionization energy decreases down a group due to increased atomic size and decreased effective nuclear charge on the outermost electron. - **Conclusion**: Lithium has a greater ionization energy than Sodium. This option is **correct**. ### Final Conclusion - The correct pairs regarding ionization energy are: - **Option 2**: Thallium has greater ionization energy than Gallium. - **Option 3**: Nitrogen has greater ionization energy than Oxygen. - **Option 4**: Lithium has greater ionization energy than Sodium.
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