He and Be both have the same outer electronic configuration like `ns^(2)` type.
Statement-2 : Both are chemically inert.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-4
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-4
C. Statement-1 is True, Statement-2 is False
D. Statement-1 is False, Statement-2 is True

Answer

To analyze the given statements about helium (He) and beryllium (Be), we can break down the solution step by step.

### Step 1: Evaluate Statement 1
**Statement 1:** "He and Be both have the same outer electronic configuration like `ns^(2)` type."

- **Analysis:**
- The electronic configuration of helium (He) is `1s^2`.
- The electronic configuration of beryllium (Be) is `1s^2 2s^2`.
- Both elements indeed have an outer electronic configuration that can be described as `ns^2` (where n is the principal quantum number).

- **Conclusion:** Statement 1 is **correct**.

### Step 2: Evaluate Statement 2
**Statement 2:** "Both are chemically inert."

- **Analysis:**
- Helium (He) is a noble gas and is chemically inert due to its fully filled outer shell (1s^2).
- Beryllium (Be), on the other hand, is not chemically inert. It is reactive because it has a vacant 2p orbital, which allows it to form compounds.

- **Conclusion:** Statement 2 is **incorrect**.

### Step 3: Relationship Between the Statements
- Since Statement 1 is correct and Statement 2 is incorrect, Statement 2 does not serve as an explanation for Statement 1.

### Final Conclusion
- The correct evaluation of the statements is that Statement 1 is true, while Statement 2 is false.

### Answer
- The correct option is: Statement 1 is true, but Statement 2 is false.

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